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Store In Array , Num1.. Num2 - Dream In Code


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    2 Replies - 64 Views - Last Post: Yesterday, 11:55 PM Rate Topic: -----

    #1 another ?Icon User is offline

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    Posted Yesterday, 10:55 PM

    i want from user enter any number , then i print it ,then the user enter second number and print the first number with the second..
    how i can do it ???
    
 import java.util.Scanner;  public class TTRY {      public static void main(String[] args) {      Scanner scan=new Scanner(System.in);           int array[]=new int[5];       for(int i: array){     	 System.out.print("\nEnter Number: ");     	 array[i]= scan.nextInt();          if(array[i] == array[i]){          printArray(array);          }}    	} 	 public static void printArray(int arr[]){ 	        int n = arr.length; 	        for (int i = 0; i < n; i++) { 	            System.out.print(arr[i] + " ");         }  }} 


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    Replies To: store in array , num1.. num2 ....

    #2 Bountyhunter1234 ?Icon User is online

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    Re: store in array , num1.. num2 ....

    Posted Yesterday, 11:02 PM

    your using the wrong type of for statement instead of for each use a for(int index = 0; index < array.length; index++){


    #3 another ?Icon User is offline

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    Re: store in array , num1.. num2 ....

    Posted Yesterday, 11:55 PM

    View Postanother, on 10 May 2013 - 10:55 PM, said:

    i want from user enter any number , then i print it ,then the user enter second number and print the first number with the second..
    how i can do it ???
    
 import java.util.Scanner;  public class TTRY {      public static void main(String[] args) {      Scanner scan=new Scanner(System.in);           int array[]=new int[5];       for(int i: array){     	 System.out.print("\nEnter Number: ");     	 array[i]= scan.nextInt();          printArray(array);          }}    	} 	 public static void printArray(int arr[]){ 	        int n = arr.length; 	        for (int i = 0; i < n; i++) { 	            System.out.print(arr[i] + " ");         }  }} 


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